Solucionario Ciencia E Ingenieria De Los Materiales Askeland 3 Edicion -

Buscamos en tabla de erf(z): erf(z) = 0,6818 → z ≈ 0,71 (interpolando).

[ 0,71 = \frac{0,0008}{2\sqrt{(1.4\times10^{-11}) t}} ]

[ \frac{1,2 - 0,45}{1,2 - 0,10} = \frac{0,75}{1,10} = 0,6818 ] Buscamos en tabla de erf(z): erf(z) = 0,6818

[ \sqrt{t} = \frac{0,0008}{5.313\times10^{-6}} \approx 150,6 ]

[ 0,71 = \frac{0,0008}{7.4834\times10^{-6} \sqrt{t}} ] [ 5.313\times10^{-6} \sqrt{t} = 0

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[ 5.313\times10^{-6} \sqrt{t} = 0,0008 ] 2% ) C

Usamos la función error complementaria:

( t \approx 6,3 , \text{horas} ).

Donde: ( C_s = 1,2% ) C, ( C_0 = 0,10% ) C, ( C_x = 0,45% ) C, ( x = 0,0008 , \text{m} ), ( D = 1.4\times10^{-11} , \text{m}^2/\text{s} ).