θ = tan^(-1)(-30.3 km / 37.5 km) = -38.3°
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A car travels 20.0 km due north and then 35.0 km in a direction 60.0° west of north. Find the magnitude and direction of the car's resultant displacement.
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The direction is:
R = √(37.5 km)^2 + (-30.3 km)^2 = 48.2 km
North component: 20.0 km + 35.0 km * cos(60.0°) = 20.0 km + 17.5 km = 37.5 km West component: -35.0 km * sin(60.0°) = -30.3 km
F = mg * sin(30.0°)
Using Newton's second law:
The resultant displacement is: