Design And Analysis Of Experiments Chapter 8 Solutions Link

Better to compute systematically:

y = [25, 22, 20, 30, 24, 28, 32, 35]

Effect B: Contrast = (-y_(1) - y_a + y_b + y_ab - y_c - y_ac + y_bc + y_abc) = (-25 -22 +20 +30 -24 -28 +32 +35) = (-47 +50=3 -24=-21 -28=-49 +32=-17 +35=18) → Wait, recalc carefully:

(A = (-1, +1, -1, +1, -1, +1, -1, +1) ) (B = (-1, -1, +1, +1, -1, -1, +1, +1)) (C = (-1, -1, -1, -1, +1, +1, +1, +1)) design and analysis of experiments chapter 8 solutions

B: -25-22+20+30-24-28+32+35 = (-47+20=-27; -27+30=3; 3-24=-21; -21-28=-49; -49+32=-17; -17+35=18) ✅

: A (2^3) design with 2 replicates, each in 2 blocks. In replicate I, confound ABC; in replicate II, confound AB. Estimate all effects.

Order: (1), a, b, ab, c, ac, bc, abc.

A: -25+22-20+30-24+28-32+35 = (-25+22=-3; -3-20=-23; -23+30=7; 7-24=-17; -17+28=11; 11-32=-21; -21+35=14) ✅

:

Actually, let's structure properly:

So ABC contrast = 14. This is the difference between Block 1 and Block 2? Let’s check block totals:

Compute: 25 1 +22 (-1)+20*(-1)+30 1 +24 (-1)+28 1 +32 1 +35*(-1) = 25 -22 -20 +30 -24 +28 +32 -35 = (25-22=3; 3-20=-17; -17+30=13; 13-24=-11; -11+28=17; 17+32=49; 49-35=14).